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Revert TT replacement strategy changes (#380)

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It could cause problems with high depths and long time controls

Bench: 8626315

Resolves #390
This commit is contained in:
mstembera 2015-08-08 03:06:32 -07:00 • committed by Joona Kiiski
parent e6310b3469
commit 1aae35b8b7
1 changed files with 6 additions and 5 deletions
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11
src/tt.cpp
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@ -66,9 +66,9 @@ void TranspositionTable::clear() {
/// TranspositionTable::probe() looks up the current position in the transposition
/// table. It returns true and a pointer to the TTEntry if the position is found.
/// Otherwise, it returns false and a pointer to an empty or least valuable TTEntry
/// to be replaced later. TTEntry t1 is considered more valuable than TTEntry t2 if
/// both are from the current search and the depth of t1 is greater than the depth of t2,
/// or if t1 is from a previous search but its depth is at least 8 ply deeper than t2.
/// to be replaced later. A TTEntry t1 is considered to be more valuable than a
/// TTEntry t2 if t1 is from the current search and t2 is from a previous search,
/// or if the depth of t1 is bigger than the depth of t2.
TTEntry* TranspositionTable::probe(const Key key, bool& found) const {
@ -87,8 +87,9 @@ TTEntry* TranspositionTable::probe(const Key key, bool& found) const {
// Find an entry to be replaced according to the replacement strategy
TTEntry* replace = tte;
for (int i = 1; i < ClusterSize; ++i)
if ( (( tte[i].genBound8 & 0xFC) == generation8) * 8 * ONE_PLY + tte[i].depth8
< ((replace->genBound8 & 0xFC) == generation8) * 8 * ONE_PLY + replace->depth8)
if ( (( tte[i].genBound8 & 0xFC) == generation8)
- ((replace->genBound8 & 0xFC) == generation8)
- (tte[i].depth8 < replace->depth8) < 0)
replace = &tte[i];
return found = false, replace;