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Remove AdjacentFiles
This is a non-functional simplification that removes the AdjacentFiles array. This array is simple enough to calculate that the pre-calculated array provides no benefit. Reduces the memory footprint. STC LLR: 2.96 (-2.94,2.94) [-3.00,1.00] Total: 74839 W: 16390 L: 16373 D: 42076 http://tests.stockfishchess.org/tests/view/5c3d75920ebc596a450cfb67 No functionnal change
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2 changed files with 2 additions and 7 deletions
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@ -29,7 +29,6 @@ int SquareDistance[SQUARE_NB][SQUARE_NB];
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Bitboard SquareBB[SQUARE_NB];
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Bitboard FileBB[FILE_NB];
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Bitboard RankBB[RANK_NB];
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Bitboard AdjacentFilesBB[FILE_NB];
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Bitboard ForwardRanksBB[COLOR_NB][RANK_NB];
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Bitboard BetweenBB[SQUARE_NB][SQUARE_NB];
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Bitboard LineBB[SQUARE_NB][SQUARE_NB];
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@ -97,9 +96,6 @@ void Bitboards::init() {
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for (Rank r = RANK_1; r <= RANK_8; ++r)
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RankBB[r] = r > RANK_1 ? RankBB[r - 1] << 8 : Rank1BB;
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for (File f = FILE_A; f <= FILE_H; ++f)
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AdjacentFilesBB[f] = (f > FILE_A ? FileBB[f - 1] : 0) | (f < FILE_H ? FileBB[f + 1] : 0);
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for (Rank r = RANK_1; r < RANK_8; ++r)
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ForwardRanksBB[WHITE][r] = ~(ForwardRanksBB[BLACK][r + 1] = ForwardRanksBB[BLACK][r] | RankBB[r]);
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@ -107,7 +103,7 @@ void Bitboards::init() {
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for (Square s = SQ_A1; s <= SQ_H8; ++s)
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{
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ForwardFileBB [c][s] = ForwardRanksBB[c][rank_of(s)] & FileBB[file_of(s)];
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PawnAttackSpan[c][s] = ForwardRanksBB[c][rank_of(s)] & AdjacentFilesBB[file_of(s)];
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PawnAttackSpan[c][s] = ForwardRanksBB[c][rank_of(s)] & adjacent_files_bb(file_of(s));
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PassedPawnMask[c][s] = ForwardFileBB [c][s] | PawnAttackSpan[c][s];
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}
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@ -65,7 +65,6 @@ extern int SquareDistance[SQUARE_NB][SQUARE_NB];
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extern Bitboard SquareBB[SQUARE_NB];
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extern Bitboard FileBB[FILE_NB];
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extern Bitboard RankBB[RANK_NB];
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extern Bitboard AdjacentFilesBB[FILE_NB];
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extern Bitboard ForwardRanksBB[COLOR_NB][RANK_NB];
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extern Bitboard BetweenBB[SQUARE_NB][SQUARE_NB];
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extern Bitboard LineBB[SQUARE_NB][SQUARE_NB];
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@ -195,7 +194,7 @@ constexpr Bitboard double_pawn_attacks_bb(Bitboard b) {
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/// adjacent files of the given one.
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inline Bitboard adjacent_files_bb(File f) {
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return AdjacentFilesBB[f];
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return shift<EAST>(FileBB[f]) | shift<WEST>(FileBB[f]);
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}
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