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Remove some difficult to understand C++11 constructs
Code like this is more a case of showing off one's C++ knowledge, rather than using it adequately, IMHO. **First loop (std::generate)** Iterators are inadequate here, because they lose the key information which is idx. As a result, we need to carry a redundant idx variable, and increment it along the way. Very clumsy. Usage of std::generate and a lambda function only obfuscate the code, which is merely a simple and stupid loop over the elements of a vector. **Second loop (std::accumulate)** This code is thoroughlly incomprehensible. Restore the original, which was much simpler to understand. **Third loop (range based loop)** Again, a range based loop is inadequate, because we lose idx! To resolve this artificially created problem, the data model was made redundant (idx is a data member of db[] elements!?), which is ugly and unjustified. A simple and stupid for loop with idx does the job much better. No functional change. Resolves #313
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1 changed files with 9 additions and 9 deletions
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@ -64,7 +64,6 @@ namespace {
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template<Color Us> Result classify(const std::vector<KPKPosition>& db);
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unsigned id;
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Color us;
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Square ksq[COLOR_NB], psq;
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Result result;
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@ -85,20 +84,22 @@ bool Bitbases::probe(Square wksq, Square wpsq, Square bksq, Color us) {
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void Bitbases::init() {
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std::vector<KPKPosition> db(MAX_INDEX);
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unsigned id = 0;
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unsigned idx, repeat = 1;
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// Initialize db with known win / draw positions
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std::generate(db.begin(), db.end(), [&id](){ return KPKPosition(id++); });
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for (idx = 0; idx < MAX_INDEX; ++idx)
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db[idx] = KPKPosition(idx);
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// Iterate through the positions until none of the unknown positions can be
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// changed to either wins or draws (15 cycles needed).
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while (std::accumulate(db.begin(), db.end(), false, [&](bool repeat, KPKPosition& pos)
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{ return (pos == UNKNOWN && pos.classify(db) != UNKNOWN) || repeat; })){}
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while (repeat)
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for (repeat = idx = 0; idx < MAX_INDEX; ++idx)
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repeat |= (db[idx] == UNKNOWN && db[idx].classify(db) != UNKNOWN);
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// Map 32 results into one KPKBitbase[] entry
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for (auto& pos : db)
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if (pos == WIN)
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KPKBitbase[pos.id / 32] |= 1 << (pos.id & 0x1F);
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for (idx = 0; idx < MAX_INDEX; ++idx)
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if (db[idx] == WIN)
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KPKBitbase[idx / 32] |= 1 << (idx & 0x1F);
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}
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@ -106,7 +107,6 @@ namespace {
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KPKPosition::KPKPosition(unsigned idx) {
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id = idx;
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ksq[WHITE] = Square((idx >> 0) & 0x3F);
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ksq[BLACK] = Square((idx >> 6) & 0x3F);
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us = Color ((idx >> 12) & 0x01);
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