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Simplify evaluate_passed_pawns

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From a suggestion by David Zar.

No functional change.
This commit is contained in:
Marco Costalba 2014-07-14 15:15:07 +02:00 • committed by lucasart
parent 67a5e1ecf9
commit 896bd917f8
1 changed files with 10 additions and 14 deletions
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24
src/evaluate.cpp
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@ -574,22 +574,18 @@ namespace {
// If the pawn is free to advance, then increase the bonus // If the pawn is free to advance, then increase the bonus
if (pos.empty(blockSq)) if (pos.empty(blockSq))
{ {
squaresToQueen = forward_bb(Us, s); // If there is a rook or queen attacking/defending the pawn from behind,
// consider all the squaresToQueen. Otherwise consider only the squares
// in the pawn's path attacked or occupied by the enemy.
defendedSquares = unsafeSquares = squaresToQueen = forward_bb(Us, s);
// If there is an enemy rook or queen attacking the pawn from behind, Bitboard bb = forward_bb(Them, s) & pos.pieces(ROOK, QUEEN) & pos.attacks_from<ROOK>(s);
// add all X-ray attacks by the rook or queen. Otherwise consider only
// the squares in the pawn's path attacked or occupied by the enemy.
if ( unlikely(forward_bb(Them, s) & pos.pieces(Them, ROOK, QUEEN))
&& (forward_bb(Them, s) & pos.pieces(Them, ROOK, QUEEN) & pos.attacks_from<ROOK>(s)))
unsafeSquares = squaresToQueen;
else
unsafeSquares = squaresToQueen & (ei.attackedBy[Them][ALL_PIECES] | pos.pieces(Them));
if ( unlikely(forward_bb(Them, s) & pos.pieces(Us, ROOK, QUEEN)) if (!(pos.pieces(Us) & bb))
&& (forward_bb(Them, s) & pos.pieces(Us, ROOK, QUEEN) & pos.attacks_from<ROOK>(s))) defendedSquares &= ei.attackedBy[Us][ALL_PIECES];
defendedSquares = squaresToQueen;
else if (!(pos.pieces(Them) & bb))
defendedSquares = squaresToQueen & ei.attackedBy[Us][ALL_PIECES]; unsafeSquares &= ei.attackedBy[Them][ALL_PIECES] | pos.pieces(Them);
// If there aren't any enemy attacks, assign a big bonus. Otherwise // If there aren't any enemy attacks, assign a big bonus. Otherwise
// assign a smaller bonus if the block square isn't attacked. // assign a smaller bonus if the block square isn't attacked.