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Constructed objects must be destructible
Pointer members of WDLEntry and DTZEntry must be null, so they can be freed. Whether unmap() behaves like free() and tolerates a NULL pointer (treated as no-op) is unclear. Better safe than sorry, so test data before calling unmap(). Simplify hasUniquePieces calculation while at it. No functional change.
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1 changed files with 9 additions and 18 deletions
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@ -481,7 +481,6 @@ WDLEntry::WDLEntry(const Position& pos, Key keys[])
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memset(this, 0, sizeof(WDLEntry));
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key = keys[WHITE];
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ready = 0;
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num = pos.count<ALL_PIECES>(WHITE) + pos.count<ALL_PIECES>(BLACK);
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symmetric = (keys[WHITE] == keys[BLACK]);
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has_pawns = pos.count<PAWN>(WHITE) + pos.count<PAWN>(BLACK);
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@ -494,26 +493,17 @@ WDLEntry::WDLEntry(const Position& pos, Key keys[])
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pawn.pawns[0] = pos.count<PAWN>(c ? WHITE : BLACK);
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pawn.pawns[1] = pos.count<PAWN>(c ? BLACK : WHITE);
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} else {
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int uniquePieces = 0;
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for (PieceType pt = PAWN; pt <= KING; ++pt)
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uniquePieces += (popcount(pos.pieces(WHITE, pt)) == 1)
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+ (popcount(pos.pieces(BLACK, pt)) == 1);
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if (uniquePieces >= 3)
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piece.hasUniquePieces = 1;
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else {
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// No unique pieces, other than W_KING and B_KING
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assert(uniquePieces == 2);
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piece.hasUniquePieces = 0;
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}
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}
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} else
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for (Color c = WHITE; c <= BLACK; ++c)
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for (PieceType pt = PAWN; pt < KING; ++pt)
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if (popcount(pos.pieces(c, pt)) == 1)
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piece.hasUniquePieces = true;
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}
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WDLEntry::~WDLEntry()
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{
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TBFile::unmap(baseAddress, mapping);
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if (baseAddress)
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TBFile::unmap(baseAddress, mapping);
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if (has_pawns)
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for (File f = FILE_A; f <= FILE_D; ++f) {
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@ -546,7 +536,8 @@ DTZEntry::DTZEntry(WDLEntry* wdl, Key k[])
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DTZEntry::~DTZEntry()
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{
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TBFile::unmap(baseAddress, mapping);
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if (baseAddress)
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TBFile::unmap(baseAddress, mapping);
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if (has_pawns)
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for (File f = FILE_A; f <= FILE_D; ++f)
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