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Avoid copy a Position to get a move's san notation
In move_to_san() we create by copy a new position just to detect if move gives check. This could be very costly in line_to_san() that calls move_to_san() for every move, so create the position only once and pass a reference to move_to_san() No functional change. Signed-off-by: Marco Costalba <mcostalba@gmail.com>
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3 changed files with 8 additions and 7 deletions
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@ -356,8 +356,9 @@ void Position::print(Move m) const {
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std::cout << std::endl;
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if (m != MOVE_NONE)
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{
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Position p(*this);
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string col = (color_of_piece_on(move_from(m)) == BLACK ? ".." : "");
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std::cout << "Move is: " << col << move_to_san(*this, m) << std::endl;
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std::cout << "Move is: " << col << move_to_san(p, m) << std::endl;
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}
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for (Rank rank = RANK_8; rank >= RANK_1; rank--)
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{
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10
src/san.cpp
10
src/san.cpp
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@ -63,7 +63,7 @@ namespace {
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/// that the move is a legal move from the position. The return value is
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/// a string containing the move in short algebraic notation.
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const string move_to_san(const Position& pos, Move m) {
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const string move_to_san(Position& pos, Move m) {
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assert(pos.is_ok());
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assert(move_is_ok(m));
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@ -123,10 +123,10 @@ const string move_to_san(const Position& pos, Move m) {
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// Position::move_is_check doesn't detect all checks (not castling moves,
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// promotions and en passant captures).
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StateInfo st;
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Position p(pos);
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p.do_move(m, st);
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if (p.is_check())
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san += p.is_mate()? "#" : "+";
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pos.do_move(m, st);
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if (pos.is_check())
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san += pos.is_mate() ? "#" : "+";
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pos.undo_move(m);
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return san;
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}
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@ -36,7 +36,7 @@
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//// Prototypes
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////
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extern const std::string move_to_san(const Position& pos, Move m);
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extern const std::string move_to_san(Position& pos, Move m);
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extern Move move_from_san(const Position& pos, const std::string& str);
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extern const std::string line_to_san(const Position& pos, Move line[], int startColumn, bool breakLines);
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extern const std::string pretty_pv(const Position& pos, int time, int depth, uint64_t nodes, Value score, ValueType type, Move pv[]);
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