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Correctly define operators in types.h

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Be consistent with the way these operators are defined
in plain C (and in C++).

Spotted by Lucas Braesch.

No functional change.

Signed-off-by: Marco Costalba <mcostalba@gmail.com>
This commit is contained in:
Marco Costalba 2011-12-24 09:55:35 +01:00
parent d543a64cc7
commit e89a8e0913
1 changed files with 4 additions and 4 deletions
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8
src/types.h
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@ -323,10 +323,10 @@ inline T operator/ (const T d, int i) { return T(int(d) / i); } \
inline T operator- (const T d) { return T(-int(d)); } \
inline T operator++ (T& d, int) {d = T(int(d) + 1); return d; } \
inline T operator-- (T& d, int) { d = T(int(d) - 1); return d; } \
inline void operator+= (T& d1, const T d2) { d1 = d1 + d2; } \
inline void operator-= (T& d1, const T d2) { d1 = d1 - d2; } \
inline void operator*= (T& d, int i) { d = T(int(d) * i); } \
inline void operator/= (T& d, int i) { d = T(int(d) / i); }
inline T& operator+= (T& d1, const T d2) { d1 = d1 + d2; return d1; } \
inline T& operator-= (T& d1, const T d2) { d1 = d1 - d2; return d1; } \
inline T& operator*= (T& d, int i) { d = T(int(d) * i); return d; } \
inline T& operator/= (T& d, int i) { d = T(int(d) / i); return d; }
ENABLE_OPERATORS_ON(Value)
ENABLE_OPERATORS_ON(PieceType)