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Simplify BlockedByKing in pawn storms
This patch is non-functional. Current master does four operations to determine whether an enemy pawn on this file is blocked by the king or not ``` f == file_of(ksq) && rkThem == relative_rank(Us, ksq) + 1 ) ``` By adding a direction (based on the template color), this is reduced to two operations. This works because b is limited to enemy pawns that are ahead of the king and on the current file. ``` shift<Down>(b) & ksq ``` I've added a line of code, but the number of executing instructions is reduced (I think). I'm not sure if this counts as a simplification, but it should theoretically be a little faster (barely). The code line length is also reduced making it a little easier to read. Closes https://github.com/official-stockfish/Stockfish/pull/1552 No functional change.
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1 changed files with 5 additions and 4 deletions
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@ -236,7 +236,8 @@ Entry* probe(const Position& pos) {
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template<Color Us>
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Value Entry::shelter_storm(const Position& pos, Square ksq) {
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constexpr Color Them = (Us == WHITE ? BLACK : WHITE);
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constexpr Color Them = (Us == WHITE ? BLACK : WHITE);
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constexpr Direction Down = (Us == WHITE ? SOUTH : NORTH);
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enum { BlockedByKing, Unopposed, BlockedByPawn, Unblocked };
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@ -257,9 +258,9 @@ Value Entry::shelter_storm(const Position& pos, Square ksq) {
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int d = std::min(f, ~f);
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safety -= ShelterWeakness[f == file_of(ksq)][d][rkUs]
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+ StormDanger
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[f == file_of(ksq) && rkThem == relative_rank(Us, ksq) + 1 ? BlockedByKing :
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rkUs == RANK_1 ? Unopposed :
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rkThem == rkUs + 1 ? BlockedByPawn : Unblocked]
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[(shift<Down>(b) & ksq) ? BlockedByKing :
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rkUs == RANK_1 ? Unopposed :
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rkThem == (rkUs + 1) ? BlockedByPawn : Unblocked]
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[d][rkThem];
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}
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